Will, Vincent and Eric shared a bag of stamps. Vincent took 27 as many stamps as Eric. Will took twice as many stamps as the total Vincent and Eric took. After Will had given 69 to Vincent and 12 to Eric, Vincent gave 6 to Eric. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Will and Vincent had at first.
| |
Vincent |
Eric |
Will |
Total |
| Before |
2 u |
7 u |
18 u |
27 u |
| Change 1 |
+ 69 |
|
- 69 |
|
| Change 2 |
|
+ 12 |
- 12 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x9 =
9 u |
1x9 =
9 u |
1x9 =
9 u |
3x9 =
27 u |
Total number of stamps that Vincent and Eric had at first
= 2 u + 7 u
= 9 u
Number of stamps that Will had at first
= 2 x 9 u
= 18 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 27 is 27.
Number of stamps that Eric received from Vincent and Will
= 9 u - 7 u
= 2 u
2 u = 12 + 6
2 u = 18
1 u = 18 ÷ 2 = 9
Difference between the number stamps that Will and Vincent had at first
= 18 u - 2 u
= 16 u
= 16 x 9
= 144
Answer(s): 144
