Vaidev, Oscar and Sam shared a bag of erasers. Oscar took 35 as many erasers as Sam. Vaidev took twice as many erasers as the total Oscar and Sam took. After Vaidev had given 40 to Oscar and 16 to Sam, Oscar gave 5 to Sam. In the end, all three of them had the same number of erasers. Find the difference between the number of erasers that Vaidev and Oscar had at first.
| |
Oscar |
Sam |
Vaidev |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 40 |
|
- 40 |
|
| Change 2 |
|
+ 16 |
- 16 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of erasers that Oscar and Sam had at first
= 3 u + 5 u
= 8 u
Number of erasers that Vaidev had at first
= 2 x 8 u
= 16 u
The total number of erasers remains unchanged. Make the total number of erasers the same. LCM of 3 and 24 is 24.
Number of erasers that Sam received from Oscar and Vaidev
= 8 u - 5 u
= 3 u
3 u = 16 + 5
3 u = 21
1 u = 21 ÷ 3 = 7
Difference between the number erasers that Vaidev and Oscar had at first
= 16 u - 3 u
= 13 u
= 13 x 7
= 91
Answer(s): 91
