Perry, Brandon and Pierre shared a bag of buttons. Brandon took 27 as many buttons as Pierre. Perry took thrice as many buttons as the total Brandon and Pierre took. After Perry had given 33 to Brandon and 12 to Pierre, Brandon gave 3 to Pierre. In the end, all three of them had the same number of buttons. Find the difference between the number of buttons that Perry and Brandon had at first.
| |
Brandon |
Pierre |
Perry |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 12 |
- 12 |
|
| Change 3 |
- 3 |
+ 3 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of buttons that Brandon and Pierre had at first
= 2 u + 7 u
= 12 u
Number of buttons that Perry had at first
= 3 x 12 u
= 27 u
The total number of buttons remains unchanged. Make the total number of buttons the same. LCM of 3 and 36 is 36.
Number of buttons that Pierre received from Brandon and Perry
= 12 u - 7 u
= 5 u
5 u = 12 + 3
5 u = 15
1 u = 15 ÷ 5 = 3
Difference between the number buttons that Perry and Brandon had at first
= 27 u - 2 u
= 25 u
= 25 x 3
= 75
Answer(s): 75
