Henry, Tom and Charlie shared a bag of pens. Tom took 27 as many pens as Charlie. Henry took thrice as many pens as the total Tom and Charlie took. After Henry had given 70 to Tom and 20 to Charlie, Tom gave 10 to Charlie. In the end, all three of them had the same number of pens. Find the difference between the number of pens that Henry and Tom had at first.
| |
Tom |
Charlie |
Henry |
Total |
| Before |
2 u |
7 u |
27 u |
36 u |
| Change 1 |
+ 70 |
|
- 70 |
|
| Change 2 |
|
+ 20 |
- 20 |
|
| Change 3 |
- 10 |
+ 10 |
|
|
| After |
1x12 =
12 u |
1x12 =
12 u |
1x12 =
12 u |
3x12 =
36 u |
Total number of pens that Tom and Charlie had at first
= 2 u + 7 u
= 12 u
Number of pens that Henry had at first
= 3 x 12 u
= 27 u
The total number of pens remains unchanged. Make the total number of pens the same. LCM of 3 and 36 is 36.
Number of pens that Charlie received from Tom and Henry
= 12 u - 7 u
= 5 u
5 u = 20 + 10
5 u = 30
1 u = 30 ÷ 5 = 6
Difference between the number pens that Henry and Tom had at first
= 27 u - 2 u
= 25 u
= 25 x 6
= 150
Answer(s): 150
