Jack, Owen and Ivan shared a bag of stamps. Owen took 25 as many stamps as Ivan. Jack took twice as many stamps as the total Owen and Ivan took. After Jack had given 36 to Owen and 6 to Ivan, Owen gave 6 to Ivan. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Jack and Owen had at first.
| |
Owen |
Ivan |
Jack |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 36 |
|
- 36 |
|
| Change 2 |
|
+ 6 |
- 6 |
|
| Change 3 |
- 6 |
+ 6 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of stamps that Owen and Ivan had at first
= 2 u + 5 u
= 7 u
Number of stamps that Jack had at first
= 2 x 7 u
= 14 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 21 is 21.
Number of stamps that Ivan received from Owen and Jack
= 7 u - 5 u
= 2 u
2 u = 6 + 6
2 u = 12
1 u = 12 ÷ 2 = 6
Difference between the number stamps that Jack and Owen had at first
= 14 u - 2 u
= 12 u
= 12 x 6
= 72
Answer(s): 72
