Cody, Flynn and Fred shared a bag of marbles. Flynn took 25 as many marbles as Fred. Cody took twice as many marbles as the total Flynn and Fred took. After Cody had given 33 to Flynn and 2 to Fred, Flynn gave 8 to Fred. In the end, all three of them had the same number of marbles. Find the difference between the number of marbles that Cody and Flynn had at first.
| |
Flynn |
Fred |
Cody |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 2 |
- 2 |
|
| Change 3 |
- 8 |
+ 8 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of marbles that Flynn and Fred had at first
= 2 u + 5 u
= 7 u
Number of marbles that Cody had at first
= 2 x 7 u
= 14 u
The total number of marbles remains unchanged. Make the total number of marbles the same. LCM of 3 and 21 is 21.
Number of marbles that Fred received from Flynn and Cody
= 7 u - 5 u
= 2 u
2 u = 2 + 8
2 u = 10
1 u = 10 ÷ 2 = 5
Difference between the number marbles that Cody and Flynn had at first
= 14 u - 2 u
= 12 u
= 12 x 5
= 60
Answer(s): 60
