Tom, Owen and Liam shared a bag of stamps. Owen took 27 as many stamps as Liam. Tom took twice as many stamps as the total Owen and Liam took. After Tom had given 32 to Owen and 4 to Liam, Owen gave 4 to Liam. In the end, all three of them had the same number of stamps. Find the difference between the number of stamps that Tom and Owen had at first.
| |
Owen |
Liam |
Tom |
Total |
| Before |
2 u |
7 u |
18 u |
27 u |
| Change 1 |
+ 32 |
|
- 32 |
|
| Change 2 |
|
+ 4 |
- 4 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x9 =
9 u |
1x9 =
9 u |
1x9 =
9 u |
3x9 =
27 u |
Total number of stamps that Owen and Liam had at first
= 2 u + 7 u
= 9 u
Number of stamps that Tom had at first
= 2 x 9 u
= 18 u
The total number of stamps remains unchanged. Make the total number of stamps the same. LCM of 3 and 27 is 27.
Number of stamps that Liam received from Owen and Tom
= 9 u - 7 u
= 2 u
2 u = 4 + 4
2 u = 8
1 u = 8 ÷ 2 = 4
Difference between the number stamps that Tom and Owen had at first
= 18 u - 2 u
= 16 u
= 16 x 4
= 64
Answer(s): 64
