Fabian, Vaidev and Owen shared a bag of coins. Vaidev took 35 as many coins as Owen. Fabian took twice as many coins as the total Vaidev and Owen took. After Fabian had given 42 to Vaidev and 22 to Owen, Vaidev gave 2 to Owen. In the end, all three of them had the same number of coins. Find the difference between the number of coins that Fabian and Vaidev had at first.
| |
Vaidev |
Owen |
Fabian |
Total |
| Before |
3 u |
5 u |
16 u |
24 u |
| Change 1 |
+ 42 |
|
- 42 |
|
| Change 2 |
|
+ 22 |
- 22 |
|
| Change 3 |
- 2 |
+ 2 |
|
|
| After |
1x8 =
8 u |
1x8 =
8 u |
1x8 =
8 u |
3x8 =
24 u |
Total number of coins that Vaidev and Owen had at first
= 3 u + 5 u
= 8 u
Number of coins that Fabian had at first
= 2 x 8 u
= 16 u
The total number of coins remains unchanged. Make the total number of coins the same. LCM of 3 and 24 is 24.
Number of coins that Owen received from Vaidev and Fabian
= 8 u - 5 u
= 3 u
3 u = 22 + 2
3 u = 24
1 u = 24 ÷ 3 = 8
Difference between the number coins that Fabian and Vaidev had at first
= 16 u - 3 u
= 13 u
= 13 x 8
= 104
Answer(s): 104
