Albert, Jenson and Bobby shared a bag of cards. Jenson took 25 as many cards as Bobby. Albert took twice as many cards as the total Jenson and Bobby took. After Albert had given 59 to Jenson and 11 to Bobby, Jenson gave 9 to Bobby. In the end, all three of them had the same number of cards. Find the difference between the number of cards that Albert and Jenson had at first.
| |
Jenson |
Bobby |
Albert |
Total |
| Before |
2 u |
5 u |
14 u |
21 u |
| Change 1 |
+ 59 |
|
- 59 |
|
| Change 2 |
|
+ 11 |
- 11 |
|
| Change 3 |
- 9 |
+ 9 |
|
|
| After |
1x7 =
7 u |
1x7 =
7 u |
1x7 =
7 u |
3x7 =
21 u |
Total number of cards that Jenson and Bobby had at first
= 2 u + 5 u
= 7 u
Number of cards that Albert had at first
= 2 x 7 u
= 14 u
The total number of cards remains unchanged. Make the total number of cards the same. LCM of 3 and 21 is 21.
Number of cards that Bobby received from Jenson and Albert
= 7 u - 5 u
= 2 u
2 u = 11 + 9
2 u = 20
1 u = 20 ÷ 2 = 10
Difference between the number cards that Albert and Jenson had at first
= 14 u - 2 u
= 12 u
= 12 x 10
= 120
Answer(s): 120
