Carl, Ken and Billy shared a bag of stickers. Ken took 27 as many stickers as Billy. Carl took four times as many stickers as the total Ken and Billy took. After Carl had given 98 to Ken and 49 to Billy, Ken gave 7 to Billy. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Carl and Ken had at first.
| |
Ken |
Billy |
Carl |
Total |
| Before |
2 u |
7 u |
36 u |
45 u |
| Change 1 |
+ 98 |
|
- 98 |
|
| Change 2 |
|
+ 49 |
- 49 |
|
| Change 3 |
- 7 |
+ 7 |
|
|
| After |
1x15 =
15 u |
1x15 =
15 u |
1x15 =
15 u |
3x15 =
45 u |
Total number of stickers that Ken and Billy had at first
= 2 u + 7 u
= 15 u
Number of stickers that Carl had at first
= 4 x 15 u
= 36 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 45 is 45.
Number of stickers that Billy received from Ken and Carl
= 15 u - 7 u
= 8 u
8 u = 49 + 7
8 u = 56
1 u = 56 ÷ 8 = 7
Difference between the number stickers that Carl and Ken had at first
= 36 u - 2 u
= 34 u
= 34 x 7
= 238
Answer(s): 238
