Tim, Sean and Owen shared a bag of stickers. Sean took 27 as many stickers as Owen. Tim took twice as many stickers as the total Sean and Owen took. After Tim had given 33 to Sean and 3 to Owen, Sean gave 5 to Owen. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Tim and Sean had at first.
| |
Sean |
Owen |
Tim |
Total |
| Before |
2 u |
7 u |
18 u |
27 u |
| Change 1 |
+ 33 |
|
- 33 |
|
| Change 2 |
|
+ 3 |
- 3 |
|
| Change 3 |
- 5 |
+ 5 |
|
|
| After |
1x9 =
9 u |
1x9 =
9 u |
1x9 =
9 u |
3x9 =
27 u |
Total number of stickers that Sean and Owen had at first
= 2 u + 7 u
= 9 u
Number of stickers that Tim had at first
= 2 x 9 u
= 18 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 27 is 27.
Number of stickers that Owen received from Sean and Tim
= 9 u - 7 u
= 2 u
2 u = 3 + 5
2 u = 8
1 u = 8 ÷ 2 = 4
Difference between the number stickers that Tim and Sean had at first
= 18 u - 2 u
= 16 u
= 16 x 4
= 64
Answer(s): 64
