Flynn, Daniel and Perry shared a bag of stickers. Daniel took 37 as many stickers as Perry. Flynn took twice as many stickers as the total Daniel and Perry took. After Flynn had given 67 to Daniel and 23 to Perry, Daniel gave 4 to Perry. In the end, all three of them had the same number of stickers. Find the difference between the number of stickers that Flynn and Daniel had at first.
| |
Daniel |
Perry |
Flynn |
Total |
| Before |
3 u |
7 u |
20 u |
30 u |
| Change 1 |
+ 67 |
|
- 67 |
|
| Change 2 |
|
+ 23 |
- 23 |
|
| Change 3 |
- 4 |
+ 4 |
|
|
| After |
1x10 =
10 u |
1x10 =
10 u |
1x10 =
10 u |
3x10 =
30 u |
Total number of stickers that Daniel and Perry had at first
= 3 u + 7 u
= 10 u
Number of stickers that Flynn had at first
= 2 x 10 u
= 20 u
The total number of stickers remains unchanged. Make the total number of stickers the same. LCM of 3 and 30 is 30.
Number of stickers that Perry received from Daniel and Flynn
= 10 u - 7 u
= 3 u
3 u = 23 + 4
3 u = 27
1 u = 27 ÷ 3 = 9
Difference between the number stickers that Flynn and Daniel had at first
= 20 u - 3 u
= 17 u
= 17 x 9
= 153
Answer(s): 153
