Jane, Eva and Roshel had a sum of money. The amount of money Jane had was
23 of the amount of money Eva had. The ratio of the amount of money Eva had to the total amount of money Roshel and Eva had was 2: 5. After Roshel gave $3 to Eva, she had as much money as Eva. How much more money did Roshel have than Jane in the end?
| Jane |
Eva |
Roshel |
2x2 =
4 u |
3x2 =
6 u |
|
| |
2x3 =
6 u |
3x3 =
9 u |
| 4 u |
6 u |
9 u |
The amount that Eva had is the repeated identity. Make the amount that Eva had the same. LCM of 3 and 2 is 6.
| |
Jane |
Eva |
Roshel |
| Before |
4 u |
6 u |
9 u |
| Change |
No change |
+ 3 |
- 3 |
| After |
4 u |
6 u + 3 |
9 u - 3 |
The amount that Roshel and Eva had in the end is the same.
9 u - 3 = 6 u + 3
9 u - 6 u = 3 + 3
3 u = 6
1 u = 6 ÷ 3 = 2
Amount that Roshel had more than Jane in the end
= 9 u - 3 - 4 u
= 5 u - 3
= 5 x 2 - 3
= 10 - 3
= $7
Answer(s): $7
