Julie, Jaslyn and Shannon had a sum of money. The amount of money Julie had was
34 of the amount of money Jaslyn had. The ratio of the amount of money Jaslyn had to the total amount of money Shannon and Jaslyn had was 2: 5. After Shannon gave $86 to Jaslyn, she had as much money as Jaslyn. How much more money did Shannon have than Julie in the end?
Julie |
Jaslyn |
Shannon |
3x1 = 3 u |
4x1 = 4 u |
|
|
2x2 = 4 u |
3x2 = 6 u |
3 u |
4 u |
6 u |
The amount that Jaslyn had is the repeated identity. Make the amount that Jaslyn had the same. LCM of 4 and 2 is 4.
|
Julie |
Jaslyn |
Shannon |
Before |
3 u |
4 u |
6 u |
Change |
No change |
+ 86 |
- 86 |
After |
3 u |
4 u + 86 |
6 u - 86 |
The amount that Shannon and Jaslyn had in the end is the same.
6 u - 86 = 4 u + 86
6 u - 4 u = 86 + 86
2 u = 172
1 u = 172 ÷ 2 = 86
Amount that Shannon had more than Julie in the end
= 6 u - 86 - 3 u
= 3 u - 86
= 3 x 86 - 86
= 258 - 86
= $172
Answer(s): $172