Tammy, Yoko and Julie had a sum of money. The amount of money Tammy had was
25 of the amount of money Yoko had. The ratio of the amount of money Yoko had to the total amount of money Julie and Yoko had was 2: 5. After Julie gave $5 to Yoko, she had as much money as Yoko. How much more money did Julie have than Tammy in the end?
Tammy |
Yoko |
Julie |
2x2 = 4 u |
5x2 = 10 u |
|
|
2x5 = 10 u |
3x5 = 15 u |
4 u |
10 u |
15 u |
The amount that Yoko had is the repeated identity. Make the amount that Yoko had the same. LCM of 5 and 2 is 10.
|
Tammy |
Yoko |
Julie |
Before |
4 u |
10 u |
15 u |
Change |
No change |
+ 5 |
- 5 |
After |
4 u |
10 u + 5 |
15 u - 5 |
The amount that Julie and Yoko had in the end is the same.
15 u - 5 = 10 u + 5
15 u - 10 u = 5 + 5
5 u = 10
1 u = 10 ÷ 5 = 2
Amount that Julie had more than Tammy in the end
= 15 u - 5 - 4 u
= 11 u - 5
= 11 x 2 - 5
= 22 - 5
= $17
Answer(s): $17