Nora, Min and Linda had a sum of money. The amount of money Nora had was
34 of the amount of money Min had. The ratio of the amount of money Min had to the total amount of money Linda and Min had was 3: 7. After Linda gave $2 to Min, she had as much money as Min. How much more money did Linda have than Nora in the end?
| Nora |
Min |
Linda |
3x3 =
9 u |
4x3 =
12 u |
|
| |
3x4 =
12 u |
4x4 =
16 u |
| 9 u |
12 u |
16 u |
The amount that Min had is the repeated identity. Make the amount that Min had the same. LCM of 4 and 3 is 12.
| |
Nora |
Min |
Linda |
| Before |
9 u |
12 u |
16 u |
| Change |
No change |
+ 2 |
- 2 |
| After |
9 u |
12 u + 2 |
16 u - 2 |
The amount that Linda and Min had in the end is the same.
16 u - 2 = 12 u + 2
16 u - 12 u = 2 + 2
4 u = 4
1 u = 4 ÷ 4 = 1
Amount that Linda had more than Nora in the end
= 16 u - 2 - 9 u
= 7 u - 2
= 7 x 1 - 2
= 7 - 2
= $5
Answer(s): $5
