Xuan, Opal and Shiyun had a sum of money. The amount of money Xuan had was
34 of the amount of money Opal had. The ratio of the amount of money Opal had to the total amount of money Shiyun and Opal had was 2: 5. After Shiyun gave $97 to Opal, she had as much money as Opal. How much more money did Shiyun have than Xuan in the end?
Xuan |
Opal |
Shiyun |
3x1 = 3 u |
4x1 = 4 u |
|
|
2x2 = 4 u |
3x2 = 6 u |
3 u |
4 u |
6 u |
The amount that Opal had is the repeated identity. Make the amount that Opal had the same. LCM of 4 and 2 is 4.
|
Xuan |
Opal |
Shiyun |
Before |
3 u |
4 u |
6 u |
Change |
No change |
+ 97 |
- 97 |
After |
3 u |
4 u + 97 |
6 u - 97 |
The amount that Shiyun and Opal had in the end is the same.
6 u - 97 = 4 u + 97
6 u - 4 u = 97 + 97
2 u = 194
1 u = 194 ÷ 2 = 97
Amount that Shiyun had more than Xuan in the end
= 6 u - 97 - 3 u
= 3 u - 97
= 3 x 97 - 97
= 291 - 97
= $194
Answer(s): $194