Tina, Kathy and Eva had a sum of money. The amount of money Tina had was ³₄ of the amount of money Kathy had. The ratio of the amount of money Kathy had to the total amount of money Eva and Kathy had was 2: 5. After Eva gave $42 to Kathy, she had as much money as Kathy. How much more money did Eva have than Tina in the end?

Tina	Kathy	Eva
3x1 = 3 u	4x1 = 4 u
	2x2 = 4 u	3x2 = 6 u
3 u	4 u	6 u

The amount that Kathy had is the repeated identity. Make the amount that Kathy had the same.  LCM of 4 and 2 is 4.

	Tina	Kathy	Eva
Before	3 u	4 u	6 u
Change	No change	+ 42	- 42
After	3 u	4 u + 42	6 u - 42

The amount that Eva and Kathy had in the end is the same.

6 u - 42 = 4 u + 42
6 u - 4 u = 42 + 42 
2 u = 84

1 u = 84 ÷ 2 = 42

Amount that Eva had more than Tina in the end
= 6 u - 42 - 3 u
= 3 u - 42
= 3 x 42 - 42
= 126 - 42
= $84

Answer(s): $84