Pamela, Kimberly and Jade had a sum of money. The amount of money Pamela had was
34 of the amount of money Kimberly had. The ratio of the amount of money Kimberly had to the total amount of money Jade and Kimberly had was 3: 8. After Jade gave $4 to Kimberly, she had as much money as Kimberly. How much more money did Jade have than Pamela in the end?
Pamela |
Kimberly |
Jade |
3x3 = 9 u |
4x3 = 12 u |
|
|
3x4 = 12 u |
5x4 = 20 u |
9 u |
12 u |
20 u |
The amount that Kimberly had is the repeated identity. Make the amount that Kimberly had the same. LCM of 4 and 3 is 12.
|
Pamela |
Kimberly |
Jade |
Before |
9 u |
12 u |
20 u |
Change |
No change |
+ 4 |
- 4 |
After |
9 u |
12 u + 4 |
20 u - 4 |
The amount that Jade and Kimberly had in the end is the same.
20 u - 4 = 12 u + 4
20 u - 12 u = 4 + 4
8 u = 8
1 u = 8 ÷ 8 = 1
Amount that Jade had more than Pamela in the end
= 20 u - 4 - 9 u
= 11 u - 4
= 11 x 1 - 4
= 11 - 4
= $7
Answer(s): $7