Xylia, Xandra and Pamela had a sum of money. The amount of money Xylia had was
34 of the amount of money Xandra had. The ratio of the amount of money Xandra had to the total amount of money Pamela and Xandra had was 3: 7. After Pamela gave $70 to Xandra, she had as much money as Xandra. How much more money did Pamela have than Xylia in the end?
Xylia |
Xandra |
Pamela |
3x3 = 9 u |
4x3 = 12 u |
|
|
3x4 = 12 u |
4x4 = 16 u |
9 u |
12 u |
16 u |
The amount that Xandra had is the repeated identity. Make the amount that Xandra had the same. LCM of 4 and 3 is 12.
|
Xylia |
Xandra |
Pamela |
Before |
9 u |
12 u |
16 u |
Change |
No change |
+ 70 |
- 70 |
After |
9 u |
12 u + 70 |
16 u - 70 |
The amount that Pamela and Xandra had in the end is the same.
16 u - 70 = 12 u + 70
16 u - 12 u = 70 + 70
4 u = 140
1 u = 140 ÷ 4 = 35
Amount that Pamela had more than Xylia in the end
= 16 u - 70 - 9 u
= 7 u - 70
= 7 x 35 - 70
= 245 - 70
= $175
Answer(s): $175