Sarah, Risa and Jade had a sum of money. The amount of money Sarah had was
23 of the amount of money Risa had. The ratio of the amount of money Risa had to the total amount of money Jade and Risa had was 2: 5. After Jade gave $24 to Risa, she had as much money as Risa. How much more money did Jade have than Sarah in the end?
Sarah |
Risa |
Jade |
2x2 = 4 u |
3x2 = 6 u |
|
|
2x3 = 6 u |
3x3 = 9 u |
4 u |
6 u |
9 u |
The amount that Risa had is the repeated identity. Make the amount that Risa had the same. LCM of 3 and 2 is 6.
|
Sarah |
Risa |
Jade |
Before |
4 u |
6 u |
9 u |
Change |
No change |
+ 24 |
- 24 |
After |
4 u |
6 u + 24 |
9 u - 24 |
The amount that Jade and Risa had in the end is the same.
9 u - 24 = 6 u + 24
9 u - 6 u = 24 + 24
3 u = 48
1 u = 48 ÷ 3 = 16
Amount that Jade had more than Sarah in the end
= 9 u - 24 - 4 u
= 5 u - 24
= 5 x 16 - 24
= 80 - 24
= $56
Answer(s): $56