Opal, Xylia and Jen had a sum of money. The amount of money Opal had was
35 of the amount of money Xylia had. The ratio of the amount of money Xylia had to the total amount of money Jen and Xylia had was 2: 5. After Jen gave $5 to Xylia, she had as much money as Xylia. How much more money did Jen have than Opal in the end?
Opal |
Xylia |
Jen |
3x2 = 6 u |
5x2 = 10 u |
|
|
2x5 = 10 u |
3x5 = 15 u |
6 u |
10 u |
15 u |
The amount that Xylia had is the repeated identity. Make the amount that Xylia had the same. LCM of 5 and 2 is 10.
|
Opal |
Xylia |
Jen |
Before |
6 u |
10 u |
15 u |
Change |
No change |
+ 5 |
- 5 |
After |
6 u |
10 u + 5 |
15 u - 5 |
The amount that Jen and Xylia had in the end is the same.
15 u - 5 = 10 u + 5
15 u - 10 u = 5 + 5
5 u = 10
1 u = 10 ÷ 5 = 2
Amount that Jen had more than Opal in the end
= 15 u - 5 - 6 u
= 9 u - 5
= 9 x 2 - 5
= 18 - 5
= $13
Answer(s): $13