Diana, Kimberly and Lynn had a sum of money. The amount of money Diana had was
45 of the amount of money Kimberly had. The ratio of the amount of money Kimberly had to the total amount of money Lynn and Kimberly had was 2: 5. After Lynn gave $85 to Kimberly, she had as much money as Kimberly. How much more money did Lynn have than Diana in the end?
Diana |
Kimberly |
Lynn |
4x2 = 8 u |
5x2 = 10 u |
|
|
2x5 = 10 u |
3x5 = 15 u |
8 u |
10 u |
15 u |
The amount that Kimberly had is the repeated identity. Make the amount that Kimberly had the same. LCM of 5 and 2 is 10.
|
Diana |
Kimberly |
Lynn |
Before |
8 u |
10 u |
15 u |
Change |
No change |
+ 85 |
- 85 |
After |
8 u |
10 u + 85 |
15 u - 85 |
The amount that Lynn and Kimberly had in the end is the same.
15 u - 85 = 10 u + 85
15 u - 10 u = 85 + 85
5 u = 170
1 u = 170 ÷ 5 = 34
Amount that Lynn had more than Diana in the end
= 15 u - 85 - 8 u
= 7 u - 85
= 7 x 34 - 85
= 238 - 85
= $153
Answer(s): $153