Xylia, Olivia and Hilda had a sum of money. The amount of money Xylia had was
45 of the amount of money Olivia had. The ratio of the amount of money Olivia had to the total amount of money Hilda and Olivia had was 2: 5. After Hilda gave $25 to Olivia, she had as much money as Olivia. How much more money did Hilda have than Xylia in the end?
Xylia |
Olivia |
Hilda |
4x2 = 8 u |
5x2 = 10 u |
|
|
2x5 = 10 u |
3x5 = 15 u |
8 u |
10 u |
15 u |
The amount that Olivia had is the repeated identity. Make the amount that Olivia had the same. LCM of 5 and 2 is 10.
|
Xylia |
Olivia |
Hilda |
Before |
8 u |
10 u |
15 u |
Change |
No change |
+ 25 |
- 25 |
After |
8 u |
10 u + 25 |
15 u - 25 |
The amount that Hilda and Olivia had in the end is the same.
15 u - 25 = 10 u + 25
15 u - 10 u = 25 + 25
5 u = 50
1 u = 50 ÷ 5 = 10
Amount that Hilda had more than Xylia in the end
= 15 u - 25 - 8 u
= 7 u - 25
= 7 x 10 - 25
= 70 - 25
= $45
Answer(s): $45