Marion, Eva and Jade had a sum of money. The amount of money Marion had was
34 of the amount of money Eva had. The ratio of the amount of money Eva had to the total amount of money Jade and Eva had was 3: 7. After Jade gave $10 to Eva, she had as much money as Eva. How much more money did Jade have than Marion in the end?
Marion |
Eva |
Jade |
3x3 = 9 u |
4x3 = 12 u |
|
|
3x4 = 12 u |
4x4 = 16 u |
9 u |
12 u |
16 u |
The amount that Eva had is the repeated identity. Make the amount that Eva had the same. LCM of 4 and 3 is 12.
|
Marion |
Eva |
Jade |
Before |
9 u |
12 u |
16 u |
Change |
No change |
+ 10 |
- 10 |
After |
9 u |
12 u + 10 |
16 u - 10 |
The amount that Jade and Eva had in the end is the same.
16 u - 10 = 12 u + 10
16 u - 12 u = 10 + 10
4 u = 20
1 u = 20 ÷ 4 = 5
Amount that Jade had more than Marion in the end
= 16 u - 10 - 9 u
= 7 u - 10
= 7 x 5 - 10
= 35 - 10
= $25
Answer(s): $25