Shiyun, Zoe and Abi had a sum of money. The amount of money Shiyun had was ³₄ of the amount of money Zoe had. The ratio of the amount of money Zoe had to the total amount of money Abi and Zoe had was 2: 5. After Abi gave $67 to Zoe, she had as much money as Zoe. How much more money did Abi have than Shiyun in the end?

Shiyun	Zoe	Abi
3x1 = 3 u	4x1 = 4 u
	2x2 = 4 u	3x2 = 6 u
3 u	4 u	6 u

The amount that Zoe had is the repeated identity. Make the amount that Zoe had the same.  LCM of 4 and 2 is 4.

	Shiyun	Zoe	Abi
Before	3 u	4 u	6 u
Change	No change	+ 67	- 67
After	3 u	4 u + 67	6 u - 67

The amount that Abi and Zoe had in the end is the same.

6 u - 67 = 4 u + 67
6 u - 4 u = 67 + 67 
2 u = 134

1 u = 134 ÷ 2 = 67

Amount that Abi had more than Shiyun in the end
= 6 u - 67 - 3 u
= 3 u - 67
= 3 x 67 - 67
= 201 - 67
= $134

Answer(s): $134