Roshel, Sabrina and Jade had a sum of money. The amount of money Roshel had was
35 of the amount of money Sabrina had. The ratio of the amount of money Sabrina had to the total amount of money Jade and Sabrina had was 4: 9. After Jade gave $65 to Sabrina, she had as much money as Sabrina. How much more money did Jade have than Roshel in the end?
Roshel |
Sabrina |
Jade |
3x4 = 12 u |
5x4 = 20 u |
|
|
4x5 = 20 u |
5x5 = 25 u |
12 u |
20 u |
25 u |
The amount that Sabrina had is the repeated identity. Make the amount that Sabrina had the same. LCM of 5 and 4 is 20.
|
Roshel |
Sabrina |
Jade |
Before |
12 u |
20 u |
25 u |
Change |
No change |
+ 65 |
- 65 |
After |
12 u |
20 u + 65 |
25 u - 65 |
The amount that Jade and Sabrina had in the end is the same.
25 u - 65 = 20 u + 65
25 u - 20 u = 65 + 65
5 u = 130
1 u = 130 ÷ 5 = 26
Amount that Jade had more than Roshel in the end
= 25 u - 65 - 12 u
= 13 u - 65
= 13 x 26 - 65
= 338 - 65
= $273
Answer(s): $273