Three years ago, Brandon's age was 25% of Jenson's age. One years from their current age, Brandon's age will be 37.5% of Jenson's age. How many years is Jenson older than Brandon?
| |
Brandon |
Jenson |
Difference |
| Before |
1x5 =
5 u |
4x5 =
20 u |
3x5 =
15 u |
| Change |
+ 3
+ 1 |
+ 3
+ 1 |
|
| After |
3x3 =
9 u |
8x3 =
24 u |
5x3 =
15 u |
25% =
25100 =
14 37.5% =
3751000 =
38The difference in the ages between Brandon and Jenson remains unchanged. Make the difference the same. LCM of 3 and 5 is 15.
Increase in Brandon's age
= 9 u - 5 u
= 4 u
4 u = 3 + 1
4 u = 4
1 u = 4 ÷ 4 = 1
Number of years that Jenson is older than Brandon
= 20 u - 5 u
= 15 u
= 15 x 1
= 15
Answer(s): 15
