Jeremiah bought some kaya and vanilla croissants in the ratio of 6 : 5. After Jeremiah's classmates ate an equal number of the two types of croissants, there were 40% fewer vanilla than kaya croissants. In the end, there were 128 croissants left. How many croissants of each type were eaten?
| |
Kaya |
Vanilla |
Difference |
| Before |
6x2 =
12 u |
5x2 =
10 u |
1x2 =
2 u |
| Change |
- 7 u |
- 7 u |
|
| After |
5 u |
3 u |
2 u |
100% - 40% = 60%
60% =
60100 =
35The difference in the number of kaya and vanilla croissants remains unchanged.
LCM of 1 and 2 = 2
Total croissants left = 5 u + 3 u = 8 u
8 u = 128
1 u = 128 ÷ 8 = 16
Total number of each type of croissants eaten
= 7 u
= 7 x 16
= 112
Answer(s): 112
