In April, Fanny and Brandon had coins in the ratio 11 : 5. In May, each of them gave away the same number of coins. Fanny then had four times as many coins as Brandon.
- Find the ratio of the number of coins Brandon had in April to the number of coins he had in May.
- Find the ratio of the total number of coins both had in April to the total number of coins both had in May.
| |
Fanny |
Brandon |
Difference |
| Before |
11x1 =
11 u |
5x1 =
5 u |
6x1 =
6 u |
| Change |
- 3 u |
- 3 u |
|
| After |
4x2 =
8 u |
1x2 =
2 u |
3x2 =
6 u |
(a)
Since Fanny and Brandon gave away the same number of coins, the difference in the number of coins between Fanny and Brandon at first and in the end remains the same.
Make the difference in the number of coins at first and in the end the same. LCM of 6 and 3 is 6.
Brandon's coins in April : Brandon's coins in May
5 : 2
(b)
Total number of coins in April
= 11 u + 5 u
= 16 u
Total number of coins in May
= 8 u + 2 u
= 10 u
Total coins in April : Total coins in May
16 : 10
(÷2)8 : 5
Answer(s): (a) 5 : 2; (b) 8 : 5
