In May, Marion and Henry had cards in the ratio 7 : 3. In June, each of them gave away the same number of cards. Marion then had four times as many cards as Henry.
- Find the ratio of the number of cards Henry had in May to the number of cards he had in June.
- Find the ratio of the total number of cards both had in May to the total number of cards both had in June.
| |
Marion |
Henry |
Difference |
| Before |
7x3 =
21 u |
3x3 =
9 u |
4x3 =
12 u |
| Change |
- 5 u |
- 5 u |
|
| After |
4x4 =
16 u |
1x4 =
4 u |
3x4 =
12 u |
(a)
Since Marion and Henry gave away the same number of cards, the difference in the number of cards between Marion and Henry at first and in the end remains the same.
Make the difference in the number of cards at first and in the end the same. LCM of 4 and 3 is 12.
Henry's cards in May : Henry's cards in June
9 : 4
(b)
Total number of cards in May
= 21 u + 9 u
= 30 u
Total number of cards in June
= 16 u + 4 u
= 20 u
Total cards in May : Total cards in June
30 : 20
(÷10)3 : 2
Answer(s): (a) 9 : 4; (b) 3 : 2
