In April, Pamela and Howard had coins in the ratio 4 : 3. In May, each of them gave away the same number of coins. Pamela then had thrice as many coins as Howard.
- Find the ratio of the number of coins Howard had in April to the number of coins he had in May.
- Find the ratio of the total number of coins both had in April to the total number of coins both had in May.
| |
Pamela |
Howard |
Difference |
| Before |
4x2 =
8 u |
3x2 =
6 u |
1x2 =
2 u |
| Change |
- 5 u |
- 5 u |
|
| After |
3x1 =
3 u |
1x1 =
1 u |
2x1 =
2 u |
(a)
Since Pamela and Howard gave away the same number of coins, the difference in the number of coins between Pamela and Howard at first and in the end remains the same.
Make the difference in the number of coins at first and in the end the same. LCM of 1 and 2 is 2.
Howard's coins in April : Howard's coins in May
6 : 1
(b)
Total number of coins in April
= 8 u + 6 u
= 14 u
Total number of coins in May
= 3 u + 1 u
= 4 u
Total coins in April : Total coins in May
14 : 4
(÷2)7 : 2
Answer(s): (a) 6 : 1; (b) 7 : 2
