In May, Yen and Daniel had coins in the ratio 7 : 4. In June, each of them gave away the same number of coins. Yen then had thrice as many coins as Daniel.
- Find the ratio of the number of coins Daniel had in May to the number of coins he had in June.
- Find the ratio of the total number of coins both had in May to the total number of coins both had in June.
| |
Yen |
Daniel |
Difference |
| Before |
7x2 =
14 u |
4x2 =
8 u |
3x2 =
6 u |
| Change |
- 5 u |
- 5 u |
|
| After |
3x3 =
9 u |
1x3 =
3 u |
2x3 =
6 u |
(a)
Since Yen and Daniel gave away the same number of coins, the difference in the number of coins between Yen and Daniel at first and in the end remains the same.
Make the difference in the number of coins at first and in the end the same. LCM of 3 and 2 is 6.
Daniel's coins in May : Daniel's coins in June
8 : 3
(b)
Total number of coins in May
= 14 u + 8 u
= 22 u
Total number of coins in June
= 9 u + 3 u
= 12 u
Total coins in May : Total coins in June
22 : 12
(÷2)11 : 6
Answer(s): (a) 8 : 3; (b) 11 : 6
