In May, Yoko and Jeremy had coins in the ratio 3 : 2. In June, each of them gave away the same number of coins. Yoko then had four times as many coins as Jeremy.
- Find the ratio of the number of coins Jeremy had in May to the number of coins he had in June.
- Find the ratio of the total number of coins both had in May to the total number of coins both had in June.
| |
Yoko |
Jeremy |
Difference |
| Before |
3x3 =
9 u |
2x3 =
6 u |
1x3 =
3 u |
| Change |
- 5 u |
- 5 u |
|
| After |
4x1 =
4 u |
1x1 =
1 u |
3x1 =
3 u |
(a)
Since Yoko and Jeremy gave away the same number of coins, the difference in the number of coins between Yoko and Jeremy at first and in the end remains the same.
Make the difference in the number of coins at first and in the end the same. LCM of 1 and 3 is 3.
Jeremy's coins in May : Jeremy's coins in June
6 : 1
(b)
Total number of coins in May
= 9 u + 6 u
= 15 u
Total number of coins in June
= 4 u + 1 u
= 5 u
Total coins in May : Total coins in June
15 : 5
(÷5)3 : 1
Answer(s): (a) 6 : 1; (b) 3 : 1
