Riordan had a total of 175 silver and blue balloons. After giving away
57 of the silver balloons and 76 blue balloons, there was an equal number of silver and blue balloons left. How many silver balloons did he have at first?
|
Silver balloons |
Blue balloons |
Total |
Before |
7 u |
2 u + 76 |
175 |
Change |
- 5 u |
- 76 |
|
After |
2 u |
2 u |
|
Total number of balloons at first
= 7 u + 2 u + 76
= 9 u + 76
9 u + 76 = 175
9 u = 175 - 76
9 u = 99
1 u = 99 ÷ 9 = 11
Number of silver balloons that Riordan had at first
= 7 u
= 7 x 11
= 77
Answer(s): 77