Gabriel had a total of 176 black and green stars. After giving away
13 of the black stars and 46 green stars, there was an equal number of black and green stars left. How many black stars did he have at first?
| |
Black stars |
Green stars |
Total |
| Before |
3 u |
2 u + 46 |
176 |
| Change |
- 1 u |
- 46 |
|
| After |
2 u |
2 u |
|
Total number of stars at first
= 3 u + 2 u + 46
= 5 u + 46
5 u + 46 = 176
5 u = 176 - 46
5 u = 130
1 u = 130 ÷ 5 = 26
Number of black stars that Gabriel had at first
= 3 u
= 3 x 26
= 78
Answer(s): 78
