Flynn had a total of 127 white and gold flags. After giving away
12 of the white flags and 40 gold flags, there was an equal number of white and gold flags left. How many white flags did he have at first?
| |
White flags |
Gold flags |
Total |
| Before |
2 u |
1 u + 40 |
127 |
| Change |
- 1 u |
- 40 |
|
| After |
1 u |
1 u |
|
Total number of flags at first
= 2 u + 1 u + 40
= 3 u + 40
3 u + 40 = 127
3 u = 127 - 40
3 u = 87
1 u = 87 ÷ 3 = 29
Number of white flags that Flynn had at first
= 2 u
= 2 x 29
= 58
Answer(s): 58
