Lee had a total of 139 red and purple flags. After giving away
34 of the red flags and 74 purple flags, there was an equal number of red and purple flags left. How many red flags did he have at first?
|
Red flags |
Purple flags |
Total |
Before |
4 u |
1 u + 74 |
139 |
Change |
- 3 u |
- 74 |
|
After |
1 u |
1 u |
|
Total number of flags at first
= 4 u + 1 u + 74
= 5 u + 74
5 u + 74 = 139
5 u = 139 - 74
5 u = 65
1 u = 65 ÷ 5 = 13
Number of red flags that Lee had at first
= 4 u
= 4 x 13
= 52
Answer(s): 52