Daniel had a total of 187 blue and grey balls. After giving away
12 of the blue balls and 73 grey balls, there was an equal number of blue and grey balls left. How many blue balls did he have at first?
| |
Blue balls |
Grey balls |
Total |
| Before |
2 u |
1 u + 73 |
187 |
| Change |
- 1 u |
- 73 |
|
| After |
1 u |
1 u |
|
Total number of balls at first
= 2 u + 1 u + 73
= 3 u + 73
3 u + 73 = 187
3 u = 187 - 73
3 u = 114
1 u = 114 ÷ 3 = 38
Number of blue balls that Daniel had at first
= 2 u
= 2 x 38
= 76
Answer(s): 76
