Albert had a total of 154 silver and black balls. After giving away
15 of the silver balls and 46 black balls, there was an equal number of silver and black balls left. How many silver balls did he have at first?
| |
Silver balls |
Black balls |
Total |
| Before |
5 u |
4 u + 46 |
154 |
| Change |
- 1 u |
- 46 |
|
| After |
4 u |
4 u |
|
Total number of balls at first
= 5 u + 4 u + 46
= 9 u + 46
9 u + 46 = 154
9 u = 154 - 46
9 u = 108
1 u = 108 ÷ 9 = 12
Number of silver balls that Albert had at first
= 5 u
= 5 x 12
= 60
Answer(s): 60
