Ahmad had a total of 177 yellow and black flags. After giving away
45 of the yellow flags and 45 black flags, there was an equal number of yellow and black flags left. How many yellow flags did he have at first?
| |
Yellow flags |
Black flags |
Total |
| Before |
5 u |
1 u + 45 |
177 |
| Change |
- 4 u |
- 45 |
|
| After |
1 u |
1 u |
|
Total number of flags at first
= 5 u + 1 u + 45
= 6 u + 45
6 u + 45 = 177
6 u = 177 - 45
6 u = 132
1 u = 132 ÷ 6 = 22
Number of yellow flags that Ahmad had at first
= 5 u
= 5 x 22
= 110
Answer(s): 110
