There are 25% more silver coins than green coins in a bag. After Tommy removed 40% of the silver coins and increased the number of green coins by 30%, there are now 132 fewer silver coins than green coins. Find the number of green coins at first.
|
Silver |
Green |
Before |
5 u |
4 u |
Change |
- 2 u |
+ 1.2 u |
After |
3 u |
5.2 u |
Number of silver coins in percentage
= 100% + 25%
= 125%
125% =
125100 =
54Number of silver coins that Tommy removed
= 40% x 5 u
=
40100 x 5 u
= 2 u
Number of green coins that Tommy increased
= 30% x 4 u
=
30100 x 4 u
= 1.2 u
Number of silver coins in the end
= 5 u - 2 u
= 3 u
Number of green coins in the end
= 4 u + 1.2 u
= 5.2 u
Number of fewer silver coins than green coins in the end
= 5.2 u - 3 u
= 2.2 u
2.2 u = 132
1 u = 132 ÷ 2.2 = 60
Number of green coins at first
= 4 u
= 4 x 60
= 240
Answer(s): 240