There are 25% more brown stickers than black stickers in a bag. After Valen removed 20% of the brown stickers and increased the number of black stickers by 30%, there are now 132 fewer brown stickers than black stickers. Find the number of black stickers at first.
|
Brown |
Black |
Before |
5 u |
4 u |
Change |
- 1 u |
+ 1.2 u |
After |
4 u |
5.2 u |
Number of brown stickers in percentage
= 100% + 25%
= 125%
125% =
125100 =
54Number of brown stickers that Valen removed
= 20% x 5 u
=
20100 x 5 u
= 1 u
Number of black stickers that Valen increased
= 30% x 4 u
=
30100 x 4 u
= 1.2 u
Number of brown stickers in the end
= 5 u - 1 u
= 4 u
Number of black stickers in the end
= 4 u + 1.2 u
= 5.2 u
Number of fewer brown stickers than black stickers in the end
= 5.2 u - 4 u
= 1.2 u
1.2 u = 132
1 u = 132 ÷ 1.2 = 110
Number of black stickers at first
= 4 u
= 4 x 110
= 440
Answer(s): 440