Warren and Lee collected some pens. If Warren gave Lee 53 pens, both would have an equal number of pens. If Lee gave Warren 37 pens, Warren would have 5 times as many pens as Lee. Find the number of pens each of them had.
- Warren?
- Lee?
| Case 1 |
Case 2 |
| Warren |
Lee |
Warren |
Lee |
| 3 u + 53 |
3 u - 53 |
5 u - 37 |
1 u + 37 |
| - 53 |
+ 53 |
+ 37 |
- 37 |
1x3 =
3 u |
1x3 =
3 u |
5x1 =
5 u |
1x1 =
1 u |
(a)
The total number of stamps remains unchanged in both cases. Make the total number of pens the same. LCM of 2 and 6 is 6.
The number of pens that Lee had at first is the same in both cases.
3 u - 53 = 1 u + 37
3 u - 1 u = 53 + 37
2 u = 90
1 u = 90 ÷ 2 = 45
Number of pens that Warren had
= 3 u + 53
= 3 x 45 + 53
= 188
(b)
Number of pens that Lee had
= 3 u - 53
= 3 x 45 - 53
= 82
Answer(s): (a) 188; (b) 82
