Harry and Riordan collected some stickers. If Harry gave Riordan 52 stickers, both would have an equal number of stickers. If Riordan gave Harry 44 stickers, Harry would have 4 times as many stickers as Riordan. Find the number of stickers each of them had.
- Harry?
- Riordan?
| Case 1 |
Case 2 |
| Harry |
Riordan |
Harry |
Riordan |
| 5 u + 52 |
5 u - 52 |
8 u - 44 |
2 u + 44 |
| - 52 |
+ 52 |
+ 44 |
- 44 |
1x5 =
5 u |
1x5 =
5 u |
4x2 =
8 u |
1x2 =
2 u |
(a)
The total number of stamps remains unchanged in both cases. Make the total number of stickers the same. LCM of 2 and 5 is 10.
The number of stickers that Riordan had at first is the same in both cases.
5 u - 52 = 2 u + 44
5 u - 2 u = 52 + 44
3 u = 96
1 u = 96 ÷ 3 = 32
Number of stickers that Harry had
= 5 u + 52
= 5 x 32 + 52
= 212
(b)
Number of stickers that Riordan had
= 5 u - 52
= 5 x 32 - 52
= 108
Answer(s): (a) 212; (b) 108
