Henry and Bryan collected some pens. If Henry gave Bryan 60 pens, both would have an equal number of pens. If Bryan gave Henry 39 pens, Henry would have 4 times as many pens as Bryan. Find the number of pens each of them had.
- Henry?
- Bryan?
| Case 1 |
Case 2 |
| Henry |
Bryan |
Henry |
Bryan |
| 5 u + 60 |
5 u - 60 |
8 u - 39 |
2 u + 39 |
| - 60 |
+ 60 |
+ 39 |
- 39 |
1x5 =
5 u |
1x5 =
5 u |
4x2 =
8 u |
1x2 =
2 u |
(a)
The total number of stamps remains unchanged in both cases. Make the total number of pens the same. LCM of 2 and 5 is 10.
The number of pens that Bryan had at first is the same in both cases.
5 u - 60 = 2 u + 39
5 u - 2 u = 60 + 39
3 u = 99
1 u = 99 ÷ 3 = 33
Number of pens that Henry had
= 5 u + 60
= 5 x 33 + 60
= 225
(b)
Number of pens that Bryan had
= 5 u - 60
= 5 x 33 - 60
= 105
Answer(s): (a) 225; (b) 105
