Cole had three boxes, containing a total of 770 paper bowls. The number of paper bowls in Box F to the total number of paper bowls was 3 : 7. He sold 310 paper bowls from Box G and sold ¹₄ of the paper bowls in Box H. The number of paper bowls left in Box G to the number of paper bowls left in Box H was 2 : 1. How many paper bowls were there in Box G at first?

	Box F	Box G	Box H	Total
Before	3 u	4 u (440)		7 u (770)
		6 p + 310	4 p
Change		- 310	- 1 p
			3 p
After		2x3 = 6 p	1x3 = 3 p

7 u = 770
1 u = 770 ÷ 7 = 110

Number of paper bowls in Box G and Box H at first
= 4 u
= 4 x 110
= 440

The number of bowls left in H is the repeated identity.
LCM of 1 and 3 = 3

6 p + 310 + 4 p = 440
6 p + 4 p = 440 - 310
10 p = 130

1 p = 130 ÷ 10 = 13

Number of bowls in Box G at first
= 6 p + 310
= 6 x 13 + 310
= 78 + 310
= 388

Answer(s):388