Harry had three boxes, containing a total of 1210 plastic cups. The number of plastic cups in Box U to the total number of plastic cups was 3 : 11. He sold 481 plastic cups from Box V and sold
13 of the plastic cups in Box W. The number of plastic cups left in Box V to the number of plastic cups left in Box W was 2 : 1. How many plastic cups were there in Box V at first?
|
Box U |
Box V |
Box W |
Total |
Before |
3 u
|
8 u (880)
|
11 u (1210) |
|
|
4 p + 481 |
3 p |
|
Change |
|
- 481 |
- 1 p |
|
|
|
|
2 p |
|
After |
|
2x2 = 4 p |
1x2 = 2 p |
|
11 u = 1210
1 u = 1210 ÷ 11 = 110
Number of plastic cups in Box V and Box W at first
= 8 u
= 8 x 110
= 880
The number of cups left in W is the repeated identity.
LCM of 1 and 2 = 2
4 p + 481 + 3 p = 880
4 p + 3 p = 880 - 481
7 p = 399
1 p = 399 ÷ 7 = 57
Number of cups in Box V at first
= 4 p + 481
= 4 x 57 + 481
= 228 + 481
= 709
Answer(s):709