Riordan had three boxes, containing a total of 980 paper bowls. The number of paper bowls in Box G to the total number of paper bowls was 3 : 7. He sold 336 paper bowls from Box H and sold ¹₃ of the paper bowls in Box J. The number of paper bowls left in Box H to the number of paper bowls left in Box J was 2 : 1. How many paper bowls were there in Box H at first?

	Box G	Box H	Box J	Total
Before	3 u	4 u (560)		7 u (980)
		4 p + 336	3 p
Change		- 336	- 1 p
			2 p
After		2x2 = 4 p	1x2 = 2 p

7 u = 980
1 u = 980 ÷ 7 = 140

Number of paper bowls in Box H and Box J at first
= 4 u
= 4 x 140
= 560

The number of bowls left in J is the repeated identity.
LCM of 1 and 2 = 2

4 p + 336 + 3 p = 560
4 p + 3 p = 560 - 336
7 p = 224

1 p = 224 ÷ 7 = 32

Number of bowls in Box H at first
= 4 p + 336
= 4 x 32 + 336
= 128 + 336
= 464

Answer(s):464