Peter had three boxes, containing a total of 1650 paper plates. The number of paper plates in Box E to the total number of paper plates was 3 : 11. He sold 250 paper plates from Box F and sold ¹₅ of the paper plates in Box G. The number of paper plates left in Box F to the number of paper plates left in Box G was 5 : 1. How many paper plates were there in Box F at first?

	Box E	Box F	Box G	Total
Before	3 u	8 u (1200)		11 u (1650)
		20 p + 250	5 p
Change		- 250	- 1 p
			4 p
After		5x4 = 20 p	1x4 = 4 p

11 u = 1650
1 u = 1650 ÷ 11 = 150

Number of paper plates in Box F and Box G at first
= 8 u
= 8 x 150
= 1200

The number of plates left in G is the repeated identity.
LCM of 1 and 4 = 4

20 p + 250 + 5 p = 1200
20 p + 5 p = 1200 - 250
25 p = 950

1 p = 950 ÷ 25 = 38

Number of plates in Box F at first
= 20 p + 250
= 20 x 38 + 250
= 760 + 250
= 1010

Answer(s):1010